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strtoul() Convert String to an Unsigned Long Decimal Integer
#include <stdlib.h>
unsigned long strtoul(nptr,endptr,base);
const char *nptr; Pointer to string
char **endptr; Pointer to end of scan
int base; Number base to use
strtoul() converts a string pointed to by 'nptr' to an unsigned
long-integer value. The string is a sequence of characters that can
be interpreted as a long-integer value. strtoul() stops reading the
string at the first character that cannot be recognized as part of a
long-integer value. 'endptr' points to the character that stopped the
scan. This character could be the null character that terminated the
string or the first numeric character greater than or equal to
'base'.
The string must match this sequence:
[whitespace] [sign] [0] [x] [digits]
If 'base' is between 2 and 36, then 'base' is the base of the
long-integer represented in 'nptr'. If 'base' is 0, the first few
characters of 'nptr' determine the base: If the first character is 0
and the second character is '1'-'7', the value is an octal integer;
if the first character is 0 and the second character is 'x' or 'X',
the value is a hexadecimal integer; if the first character is '1'-
'9', the value is a decimal integer.
Returns: The unsigned long value represented by the string.
-------------------------------- Example ---------------------------------
The following statements convert 'string' to an unsigned long
integer.
#include <stdlib.h>
#include <stdio.h>
main()
{
int bas2 = 2;
int bas8 = 8;
int bas16 = 16;
char *string = "127750a03";
unsigned long longint;
char *termn;
longint = strtoul(string,&termn,bas2);
printf("%s (base %d) = %u\n",string,bas2,longint);
longint = strtoul(string,&termn,bas8);
printf("%s (base %d) = %u\n",string,bas8,longint);
}
See Also:
strtod()
strtol()
atof()
atol()
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